(y^1*y^2)+(2*x*y*y^1)=4y

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Solution for (y^1*y^2)+(2*x*y*y^1)=4y equation: 


Simplifying
(y * y2) + (2x * y * y) = 4y

Multiply y * y2
(y3) + (2x * y * y) = 4y
y3 + (2x * y * y) = 4y

Multiply x * y
y3 + (2xy * y) = 4y

Multiply xy * y
y3 + (2xy2) = 4y

Reorder the terms:
(2xy2) + y3 = 4y

Solving
(2xy2) + y3 = 4y

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1y3' to each side of the equation.
(2xy2) + y3 + -1y3 = 4y + -1y3

Combine like terms: y3 + -1y3 = 0
(2xy2) + 0 = 4y + -1y3
(2xy2) = 4y + -1y3

Divide each side by '(2y2)'.
x = 2y-1 + -0.5y

Simplifying
x = 2y-1 + -0.5y

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